(2x-5)^2+6x=(x+5)(x-5)

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Solution for (2x-5)^2+6x=(x+5)(x-5) equation: 



(2x-5)^2+6x=(x+5)(x-5)

We move all terms to the left:

(2x-5)^2+6x-((x+5)(x-5))=0

We add all the numbers together, and all the variables

6x+(2x-5)^2-((x+5)(x-5))=0

We use the square of the difference formula

x^2+6x+(2x-5)^2+25=0

We move all terms containing x to the left, all other terms to the right

x^2+6x+(2x-5)^2=-25

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